16x^2+2x-3=3

Solution for 16x^2+2x-3=3 equation:

16x^2+2x-3=3

We move all terms to the left:

16x^2+2x-3-(3)=0

We add all the numbers together, and all the variables

16x^2+2x-6=0

a = 16; b = 2; c = -6;
Δ = b2-4ac
Δ = 22-4·16·(-6)
Δ = 388
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{388}=\sqrt{4*97}=\sqrt{4}*\sqrt{97}=2\sqrt{97}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{97}}{2*16}=\frac{-2-2\sqrt{97}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{97}}{2*16}=\frac{-2+2\sqrt{97}}{32}
$